It's b squared minus 4ac.
2007-11-14 02:29:53
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answer #1
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answered by SoulDawg 4 UGA 6
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You just need b² here. Also, the b in the formula is negative (which means change its sign when plugging it in).
The formula is : {-b ±√(b² - 4ac)} / 2a
2007-11-14 02:32:30
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answer #2
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answered by Don E Knows 6
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Using the Quadratic Formula to solve
ax²+bx+c=0
x = [-b ± √(b²-4ac)]/(2a)
x₊ = [-b + √(b²-4ac)]/(2a)
x₋ = [-b − √(b²-4ac)]/(2a)
2007-11-14 02:41:32
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answer #3
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answered by DWRead 7
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b^2
2007-11-14 02:30:13
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answer #4
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answered by Linda K 5
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x=[ -b +/- square root of (b^2-4ac)]/2a
b can be positive or negative. the -b means the opposite of whatever b is in teh equation
2007-11-14 02:34:36
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answer #5
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answered by mom 7
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x/5 - x/7 = 26 - x locate the Least hassle-unfastened Denominator 7x/35 - 5x/35 = 26 - x you do not could replace the different element of the equation by using fact the numbers you replaced are nevertheless the comparable values 2x/35 = 26 - x Multiply 35 the two facets 2x = 910 - 35x upload 35x to the two facets 37x = 910 Divide 37 by ability of the two facets x = 24.549 i think of I did this incorrect...
2016-09-29 05:35:31
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answer #6
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answered by quellette 4
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b^2 should be in the blank
2007-11-14 02:31:22
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answer #7
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answered by Anonymous
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x = ( - b +/- sqrt(b^2 - 4ac) ) dividedby 2a
2007-11-14 02:34:50
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answer #8
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answered by dowsann 2
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to fill in your blank, it is b squared.
I'm in college but my 8th grade algebra teacher made us memorize a song for the quadratic equation.
2007-11-14 02:31:21
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answer #9
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answered by Moto 4
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x = [ -b +/- sqrt(b^2-4ac)]/2a
2007-11-14 02:30:24
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answer #10
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answered by ironduke8159 7
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