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I forgot the equation to find x when you can't factor the polynomial... x = [b +/- sq.rt (.... - 4ac)] / 2a... Can anyone help me fill in the blank. Thanks!

2007-11-14 02:26:35 · 13 answers · asked by Anonymous in Science & Mathematics Mathematics

13 answers

It's b squared minus 4ac.

2007-11-14 02:29:53 · answer #1 · answered by SoulDawg 4 UGA 6 · 0 0

You just need b² here. Also, the b in the formula is negative (which means change its sign when plugging it in).
The formula is : {-b ±√(b² - 4ac)} / 2a

2007-11-14 02:32:30 · answer #2 · answered by Don E Knows 6 · 0 0

Using the Quadratic Formula to solve
ax²+bx+c=0

x = [-b ± √(b²-4ac)]/(2a)

x₊ = [-b + √(b²-4ac)]/(2a)
x₋ = [-b − √(b²-4ac)]/(2a)

2007-11-14 02:41:32 · answer #3 · answered by DWRead 7 · 0 0

b^2

2007-11-14 02:30:13 · answer #4 · answered by Linda K 5 · 0 0

x=[ -b +/- square root of (b^2-4ac)]/2a



b can be positive or negative. the -b means the opposite of whatever b is in teh equation

2007-11-14 02:34:36 · answer #5 · answered by mom 7 · 0 0

x/5 - x/7 = 26 - x locate the Least hassle-unfastened Denominator 7x/35 - 5x/35 = 26 - x you do not could replace the different element of the equation by using fact the numbers you replaced are nevertheless the comparable values 2x/35 = 26 - x Multiply 35 the two facets 2x = 910 - 35x upload 35x to the two facets 37x = 910 Divide 37 by ability of the two facets x = 24.549 i think of I did this incorrect...

2016-09-29 05:35:31 · answer #6 · answered by quellette 4 · 0 0

b^2 should be in the blank

2007-11-14 02:31:22 · answer #7 · answered by Anonymous · 0 0

x = ( - b +/- sqrt(b^2 - 4ac) ) dividedby 2a

2007-11-14 02:34:50 · answer #8 · answered by dowsann 2 · 0 0

to fill in your blank, it is b squared.

I'm in college but my 8th grade algebra teacher made us memorize a song for the quadratic equation.

2007-11-14 02:31:21 · answer #9 · answered by Moto 4 · 0 0

x = [ -b +/- sqrt(b^2-4ac)]/2a

2007-11-14 02:30:24 · answer #10 · answered by ironduke8159 7 · 0 0

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