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1. Find the distance of 5x - 12y = 26 from the origin

2.Find the distance between the line 5x -12y = 26 and the point A( 3,-2)

Please Help ASAP!
Many Thankings xx

2007-11-14 02:21:47 · 5 answers · asked by Jessa 2 in Science & Mathematics Mathematics

5 answers

1) y = 5/12x + 13/6
m=5/12
slope of line perp is inverse negative( flip the fraction and change the sign)
use point slope formula
http://www.algebrahelp.com/messageboards...
find this point use in(a^2 + b^2 = c^2) XYZ triangle z being hypotenuse and therefore the distance
2) y= 5/12 + 13/6
m = 5/12
find find slope of line line perpendicular again
solve for point using (3,-2) instead of origin

2007-11-14 04:24:43 · answer #1 · answered by wayne 4 · 0 0

One way to find the distance from a point to a line is to find a line perpendicular to the given line through the given point. Then find the point of intersection of the two lines, and the distance between that point and the point you are given. I seem to recall there is a formula you can use instead, but I don't remember what it is.

1. 5x - 12y = 26 has a slope of 5/12, so a line through the origin with slope -12/5 is y = -12/5 x

substitute and you get 5x + 144/5 x = 26. Solving for x, you get x = 10/13. So y = -24/13

The distance between (0,0) and (10/13, -24/13) is 2.

The method for #2 is very similar. The answer should be 1.

2007-11-14 02:33:52 · answer #2 · answered by chcandles 4 · 0 0

1) Find the line perpendicular to the line you have there, and passing through the origin. Then get the distance between the point that the two lines meet and the origin. You'll have your answer. 2) Same thing, except the point is not (0, 0), but (3, -2). I hope this helps, and also that you learn something.

2016-05-23 03:15:08 · answer #3 · answered by alida 3 · 0 0

The distance from the point (x1,y1) to the line ax+by +c = 0 is:

d = |ax1 +by1 +c|/sqrt(a^2+b^2)
Tha | | means absolute value

2007-11-14 02:44:33 · answer #4 · answered by ironduke8159 7 · 1 0

hey about your answer to my question, you're absolutely right because I'm studying nutrition in college right now but that's not what I was talking about. And for your question, I'm sorry but geometry is not my thing I'm into science and health

2007-11-14 02:43:35 · answer #5 · answered by Anonymous · 0 1

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