Determine the equation of the line that contains the points (-5,6) and (9,6)?

Answer 1

y co-ordinate is always 6
Line is y = 6

Answer 2

1.>
You can easily use the 2 points form of a straight line to find its answer, which is given as

for a line passing through points (x1,y1) & (x2,y2)
the eqn. of line is (x-x1) / (x1 -x2) = (y-y1) / (y1-y2)
hence the eqn. of line is (x+5) / -14 = (y - 6) / 0

oops..........
it is coming something like (x+5) / -14 = infinity

dont worry

in the eqn. take zero from denominator in RHS to numerator in LHS to get (y - 6) = 0
i.e. y = 6 which is the eqn. of given line.............




2.>
you can also use slope form eqn. of line i.e. y = mx + c

now 6 = -5m + c
and 6 = 9m + c

combining both eqns.
-5m+c = 9m + c
or, -5m = 9m
or, 14m = 0
or, m = 0

putting the value of m in the earlier eqn.
6 = c

now, y = mx + c
or, y = 0+6



3.>
By the way just by looking at both points you can observe that ordinate of both pts. are same (= 6)
this infer that on the graph line is parallel to x axis

a line parallel to x axis has eqn. y = K , where K is a constant

and you know very well that y= 6

Answer 3

Step 1: Solve first for the slope, m

m = (y2 -y1) ÷ (x2 - x1)
= (6 - 6) ÷ (-5 - 9)
= (0) ÷ -14
m = 0

»»»» This means that the line a HORIZONTAL LINE. Therefore, it does not have an "x" value in its equation. ««««

Your final answer is only
♥ y = 6 ♥

Answer 4

by using two point form i.e y-y1/y2-y1=x-x1/x2-x1
here y1=6, y2=6, x1=-5, x2=9
therefore equation of line is y-6/6-6=x+5/9+5
y-6/0=x+5/14
0=x+5
therefore equation of line is x=-5

Answer 5

when there ar 2 points thru which a line passes and u need the equation of the line then the formula is
(y-y1)/(x-x1)=(y2-y1)/(x2-x1)

here (x1,y1)=(-5,6) &(x2,y2)=(9,6)
now substitute this in the formula
(y-y1)/(x-x1)=(y2-y1)/(x2-x1)
(y-6)/(x+5)=(6-6)/(9+5)
(y-6)/(x+5)=(0)/(14)
(y-6)/(x+5)=0
so
(y-6)=0(x+5)
(y-6)=0
y-6=0 is the equation of the line