A pendulum of length L1 has a period T1 = 0.850 s. The length of the pendulum is adjusted to a new value L2 su

Question

A pendulum of length L1 has a period T1 = 0.850 s. The length of the pendulum is adjusted to a new value L2 such that T2 = 1.50 s. What is the ratio L2/L1?

Answer 1

T=2pi sqrt(L/g) or
L= g(T/2pi)^2
so


L1= g(T1 /2pi)^2
L2= g(T2 /2pi)^2

L2/L1=(T2/T1)^2
L2/L1= ( 1.50 /0.850)^2
L2/L1= 3.1