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Question

Find four consecutive integers whose sum is 114.) Find four consecutive integers if the sum of the first and second is 63.)Harvey plans to use 5 ft. of shelving for four shelves whose lengths are to be a series of consecutive even numbers. How many inches long should each shelf be?) Find 4 consecutive even integers whose sum is 140.) The sum of three consecutive integers is -21. Name the integers.)The sum of the least and greatest of three consecutive integers is 50. What is the middle integer?) The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers.)The sum of three consecutive odd integers is 1,509. What are the integers?) Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25.)Twice the second of two consecutive integers increased by the first is 26. Find the integers) Please help i am not cheating, i need helpand please make sure there right,

Answer 1

1. 4 consecutive integers whose sum is 114: 27+28+29+30
2. Find 4 consecutive integers if the sum of the first and second is 63: 31+32+33+34
3. Harvey plans to use 5 ft. of shelving for four shelves whose lengths are to be a series of consecutive even numbers. How many inches long should each shelf be? The length of the shelves should be 12”, 14”, 16” and 18”
4. Find 4 consecutive even integers whose sum is 140: 32, 34, 36, 38
5. The sum of three consecutive integers is 21. Name the integers: 6 + 7 + 8 = 21
6. The sum of the least and greatest of three consecutive integers is 50. What is the middle integer? 24, 25, 26 making 25 the middle integer
7. –
8. The sum of three consecutive odd integers is 1,509. What are the integers? 501, 503, 505
9. –
10. –

If you would check the semantics on the 3 remaining questions, I will be happy to answer them for you.

Answer 2

Okay, i've done some to show you how to work it out but the most important thing you need to know is:
four consectuvive intergers: x+(x+1)+(x+2)+(x+3)
four consecutive even intergers: 2x+(2x+2)+(2x+4)+(2x+6)
four consecutive off intergers:(2x-1)+[(2x-1)+2]+[(2x-1)+4]+[(2x-1)+6]

Four consecutive interger whose sum is 114:
x+(x+1)+(x+2)+(x+3)=114
4x+6=114
4x=108
x=27, the intergers are 27, 28, 29, 30

sum of first and second are 63:
x+(x+1)=63
2x+1=63
2x=62
x=31, intergers are 31, 32, 33, 34

4 consecutive even intergers whose sum is 140:
2x+(2x+2)+(2x+4)+(2x+6)=140
8x+12=140
8x=128
x=16, intergers are 32, 34, 36, 38

sum of three consecutive intergers sum is -21
x+(x+1)+(x+2)=-21
3x+3=-21
3x=-24
x=-8, intergers are -8,-7,-6

the sum of the lease and greatest of three consec intergers is 50:
x+(x+2)=50
2x+2=50
2x=48
x=24, middle interger is 25

I'm sure this is enough, so you get the general idea. If you get stuck, don't be afraid to ask your teacher, they're there to help.

Answer 3

1) 27, 28, 29, 30
2) 31, 32, 33, 34
3) 12 in, 14 in, 16 in, 18 in
4) 32, 34, 36, 38
5) -6, -7, -8
6) 25
7) -5, -6
8) 501, 503, 505
9) 7, 9, 11
10) 8, 9

7) let smaller integer be x
larger integer: 2x+7
diff. between large & small: x+7
x+7=1
x=-6
larger integer= -6+1= 5

2(-6)+7
= -12+7
=-5

Answer 4

i'm not doing all these. use your algebra skills and represent n for the first number and (n+1) as the second consecutive number and so on. So for number one:

n+n+1+n+2+n+3=114
4n=108
n=27
So it's 27, 28, 29, 30

The rest are simple. Don't make people do them all just to "check" answers. If you are really stuck, just post one or two that you need help. It would be ridiculous for me to do all of them when you can do them. If you get them wrong, so what? If it's a take-home test, this constitutes cheating.

Answer 5

find four cons integers whos sum is 114- 26,27,28,29,30.

Answer 6

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