Write the point slope form of the equation passing through the points...?

Question

Write the point slope form of the equation passing through the points...(-2,-7) and (3,1)

And what is the slope-intercept form of this as well?

Answer 1

m = (1 + 7) / (3 + 2)
m = 8 / 5

Line passes thro` (3 , 1) :-

y - 1 = (8/5) (x - 3)
y - 1 = (8/5) x - 24/5
y = (8/5) x + 5/5 - 24/5
y = (8/5) x - 19/5 is equation of straight line.

May be written as:-
5y = 8x - 19
8x - 5y - 19 = 0

Answer 2

First find the slope of the line....its (1- -7)/(3- -2) = 8/5. The point slope equation is y-y1=m(x-x1). Where m=the slope of the line. Filling in the blanks y- -7 = 8/5(x- -2). Simplified it is y+7=8/5x+16/5.

The slope intercept form of a line is y=mx+b, m=the slope and b=the y intercept of the line, y and x are constants. For this you would first need to solve the point slope equation for the point (0,y). So substitute 0 in for x and solve for y. You should get -19/5 for the y intercept. Then substitute m=8/5 and b=-19/5. You get y=8/5x-19/5.

Answer 3

m=y2-y1/x2-x1
=-7-1/-2-
=8/5
point slope form
y-1=(8/5)*(x-3)
=>8x-5y-29=0
slope itercept form
=>y=8X-29/5

Answer 4

Y=MX+B and you write the point slope yourself...


since when did it become easier to ask someone else then to just do it yourself.

how else will you learn..