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An 8 ft wall stand 27 ft from a building. Find the length of a beam that will reach the side of the building from the outside of the wall.

2007-11-13 17:15:46 · 1 answers · asked by googoogoo 2 in Science & Mathematics Mathematics

forgot to type it. but yeah, im looking for the shortest length of the beam.

2007-11-13 18:43:12 · update #1

1 answers

You want the beam of minimum length, not just any beam, right? (Otherwise, for example, a beam of length 35√2 ft. will work; it will make a 45° angle with the ground.)

See figure: http://i6.tinypic.com/82sjb6g.gif

Method 1: the length L is L1 + L2. Show that L1 = 8 csc(θ) and L2 = 27 sec(θ) so

L = 8 csc(θ) + 27 sec(θ)

Minimize L with respect to θ

(You should find that tan(θ) = 2/3.)

Method 2: By similar triangles, 8/x = y/27, so y = 216/x.

L = √[(27 + x)² + (8 + y)²] = √[(27 + x)² + (8 + 216/x)²]

Minimize L with respect to x. You should get x=12.

With either method, you will find that the minimum L is 13√13 ft.

2007-11-13 18:32:34 · answer #1 · answered by Ron W 7 · 0 0

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