This is the question:
A driver traveling east on a dirt road when he spots a pothole ahead. He slows his car from 14 m/s to 5.5 m/s in 6 sec. What is the car's decelaration?
i need to know what the formula is for deceleration!?
2007-11-13 16:16:18 · 4 answers · asked by babyshade94 1 in Science & Mathematics ➔ Physics
Thank you!
2007-11-13 16:30:58 · update #1
find the difference between 14 and 5.5
then get that range, and divide by 6
one-sixth of that number is your ratio
ratio = speed:1 second
2007-11-13 16:20:54 · answer #1 · answered by Wil 3 · 1⤊ 0⤋
Find the diff between the 2 speeds, 14 -5.5 = 8.5m/s so the car slows down 8.5 in 6 secs how much per second divide 8.5 by 6 = 8.5 / 6 = 1.41666667 m/s i guess you could right it down as the following fomula, (x - y) / t = d.... x being the higher speed, y being the slower speed, t being the time it took to decelarate, = d the rate of decelration, hope this helps!
2007-11-13 16:29:10 · answer #2 · answered by JD 3 · 0⤊ 0⤋
The formula is hinted at by its units
in this case meters/second squared
what is the change in velocity?
14 meters / second - 5.5 meters / second = 8.5 meters / second
and then divide it by how long the change took (6 seconds)
8.5 meters / second / 6 seconds =
1.417 meters / second squared
2007-11-13 16:26:36 · answer #3 · answered by don_sv_az 7 · 1⤊ 0⤋
like figuring speed of a object.
time x distance = speed
only in this case your figuring the opposite
speed/time=distance
(x-y)/T=D
(14m/s - 5.5m/s)/6s=1.41m/s Deceleration
2007-11-13 16:22:55 · answer #4 · answered by Henry 1 · 1⤊ 0⤋