can any one help with a trig problem about sin and cos being solved from 0< x< 360?

Question

2sin(squared) times x = 1 ??? it has to be a degree???

Answer 1

2sin²x = 2(sinx)² = 1

then (sinx)² = 1/2

sinx = sqrt(1/2) or sinx = -sqrt(1/2)

sinx = sqrt(1/2) = sqrt(2)/2 for x = 45 or x = 135

sinx = -sqrt(1/2) = -sqrt(2)/2 for x = 225 or x = 315°

The solutions are 45°, 135°, 225° and 315°