divide the folowing fractions 6p-18/9p divided by 3p-9/p^2+2p please show me step by step thanks?

Question

6p-18/9p divided by 3p-9/p^2+2p

Answer 1

(6p - 18)/(9p) divided by (3p - 9)/(p² + 2p) is like multiplied by the inverse (p² + 2p)(3p - 9)

We can see than
6p - 18 = 6(p - 3)
3p - 9 = 3(p - 3)
p² + 2p = p(p + 2)

then

(6p - 18)/(9p) times (p² + 2p)/(3p - 9)

= (6p - 18)(p² + 2p) divided by 9p(3p - 9)

=6(p - 3)p(p + 2) divided by 27p(p - 3)

we can simplify by 3, by (p - 3) and by p

then it's equal to

2(p + 2)/9

Answer 2

eighty one/6 + 22/3=? The denominators for eighty one/6 are 6 and 22/3 is 3. So we ought to take the effortless denominator. it is going to be 6 as 6 may be divided via 6 itself and via three. now make the denominators equivalent for the two the values. So now the figures ought to be eighty one/6+40 4/6 because of the fact the denominators are effortless now, we are in a position to simplify as (eighty one+40 4)/6 that's one hundred twenty five/6. in the comparable way you're able to do subtractions . For multiplications eighty one/6 * 22/3, basically pass divide. (eighty one/3=27.) =27*22/6=ninety 9. to divide you invert and mulitpy so it is eighty one/6 x 3/22 = 243/132