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which prediction is correct?
a. Half of the sons and none of the daughters will have hemophilia.
b. All of the daughters and none of the sons will have hemophilia.
c. Half of the daughters and none of the sons will have hemophilia.
d. All of the sons and none of the daughters will have hemophilia.
e. Half of the sons and half of the daughters will have hemophilia.

2007-11-13 15:13:35 · 3 answers · asked by tee 1 in Science & Mathematics Biology

3 answers

a) Half of the sons and none of the daughters will have hemophilia.

The hemophilia gene is on the X chromosome. A carrier female is heterozygous for hemophilia. She has one copy of the hemophilia gene on one of her X chromosomes. So her sons will have half the chance of getting the hemophilia gene.

2007-11-13 15:27:02 · answer #1 · answered by OKIM IM 7 · 1 0

When you are dealing with an "X-linked" disease, the only one affected by the disease are males who received the affected X chromosome from their mother, and females who received both affected chromosomes from mother and an affected father.
If the father does not have hemophilia, then none of the daughters can, half will be carriers. Half the sons would be expected to receive the affected X (and be affected) and half the normal X (and would be normal).

2007-11-13 15:27:57 · answer #2 · answered by a simple man 6 · 0 0

Female: XX’
Male: XY
Kids: XX, XX', XY, XY'
Answer is A, half the sons, and no daughters will have hemophilia

2007-11-13 15:23:50 · answer #3 · answered by sciteach9 2 · 1 0

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