the sum of two..?

Question

the sum of two numbers is 50.if twice the larger is subtracted from four times the smaller ,the result is 8.find the numbers.

Answer 1

x + y = 50
y = 50-x

4y - 2x = 8
4(50-x) -2x= 8
200-4x-2x=8
200-6x=8
-6x=-192

x(big number)=32
y(small number)=18

Answer 2

Let a = the larger number
Let b = the smaller number

The sum of two #s is 50: a + b = 50
Twice the larger # (2a) is subtracted from 4 times the smaller # (4b), the result is 8: 4b - 2a = 8

Set the first equal to a:
a + b - b = 50 - b
a = 50 - b

Solve these equations simultaniously by plugging your a-value into the 2nd equation:
4b - 2a = 8
4b - 2(50 - b) = 8
4b - 100 + 2b = 8

Collect like-terms:
6b -100 = 8

Solve for b:
6b = 108
b = 108/6
b = 18

Now use your b-value to find a:
(remember that a = 50 - b)
a = 50 - 18
a = 32

so a = 32 and b = 18
(Sorry if I over-simplified! :) Just trying to help!)

Answer 3

L = larger
S = smaller
L + S = 50
4S - 2L = 8

L = 50 - S
4S - 2(50-S) = 8
4S -100 + 2S = 8
6S = 108
S = 18
L = 32
check
4*18 - 2*32 = 8
72 - 64 = 8 checks

Answer 4

larger = 32
smaller = 18

Answer 5

A x+y = 50

B 4x - 2y = 8
2A 2x + 2y = 100

Add 6x = 108

x = 18
y= 32

Answer 6

x + y = 50
if 4*min(x,y) - 2*max(x,y) = 8

x = 18
y = 32

Answer 7

50=a+b
4b-2a=8
does that help?...sry im being lazy and dont wanna do the rest.