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SAYS: FIND THE SLOPE AND Y- INTERCEPT OF THE LINEAR EQUATIONS BELOW:
3X+5Y=15

AND 3X-Y=17


THNKX, 10 POINTS ! ! !

2007-11-13 14:07:55 · 13 answers · asked by chris J 1 in Science & Mathematics Mathematics

ha ha very funny, not....10 points you lost

2007-11-13 14:12:52 · update #1

SORRY WRONG EX FOR NUMBER TWO

NO. 2 IS 2X+3Y=-12

SRRY, 10 POINTS THOUGH !! :)

2007-11-13 14:16:55 · update #2

13 answers

1)
slope = 3/5. Y intercept = 3.

2)
slope = -3. Y intercept = -17

2007-11-13 14:12:17 · answer #1 · answered by Legacy 2 · 0 0

for the first problem the y intercept is 15 and the slope is -3 over 5
number 2 the y intercept is -17 and the slope is 3

2007-11-13 22:16:01 · answer #2 · answered by britt2fly 4 · 0 0

For Y intercept, set x=0
3(0)+5Y=15
5y=15
y=3

2007-11-13 22:13:35 · answer #3 · answered by Robert S 7 · 0 0

3x+5y=15 slope is-3/5 and y intercept is 3
3x-y=17 slope is 3 and y intercept is -17

2007-11-13 22:16:07 · answer #4 · answered by john 4 · 0 0

slope = -3/5
y intercept = 1

slope = 3
y intercept = -17

2007-11-13 22:13:52 · answer #5 · answered by jara 3 · 0 0

3x + 5y = 15

5y = 15-3x
y = 3 - 3x/5

The slope is -3/5 and the y intecept is (0,3).

3x - y = 17
y = 3x - 17

The slope is 3, and y intercept is (0, -17).

2007-11-13 22:12:12 · answer #6 · answered by Anonymous · 0 0

Put them in y = mx + b form, set x = 0, and solve for y. The y-value is your y-intercept.

Next, set y =0. Solve for x to get the y-intercept.

2007-11-13 22:14:11 · answer #7 · answered by Anonymous · 0 0

Solve for y, then remember y=mx +b where m is the slope and b is an intercept.

2007-11-13 22:27:09 · answer #8 · answered by Nouri K 3 · 0 0

3x + 5y = 15
5y = -3x + 15
y = -(3/5)x + 3

m = -3/5
(0, 3)

3x - y = 17
3x = 17 + y
y = -3x + 17
y = 3x - 17

m = 3
(0, -17)

2007-11-13 22:17:57 · answer #9 · answered by The Glorious S.O.B. 7 · 0 0

3x+5y=15

5y=-3x+15

y= -(3/5)x+15

SLope= -3/5

y-intercept=15


3x-y=17

-y=-3x+17
y=3x-17

slope:3

y-intercept: -17

2007-11-13 22:15:21 · answer #10 · answered by thermodynaman2004 1 · 0 0

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