The points of intersection of the graphs of xy = 20 and x^2 + y^2 = 41 are joined to form a rectangle. Find the area of the rectangle. Show and explain all work to receive credit
I know the points are (5,4),(4,5),(-4,-5),(-5,-4), I just am not sure how to figure out the area.
2007-11-13 13:52:42 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Okay, since you have the points the answer isn't too far away.
The first thing you want to do is plot the points. That will give you a general idea of where the rectangle is placed on the coordinate plane. Once you have done that use a straight-edge to connect the points. Now to find the are you need to know the length of the sides. To do this you use the distance formula which is:
square root of [(x_2-x_10)^2+(y_2-y_1)^2]
p.s. when i say x_2 it means the 2 is subscript.
once you have the sides use the area formula to figure out the area.
Don't forget units. Lol
2007-11-13 14:00:04 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First plot the graph of f(x) on a graph sheet then draw x=-a million & x=2 that are straight away strains cutting X-axis vertically. In that area in high-quality condition rectangles & triangles in accordance on your decision however the endpoint could be on the darker strains or wahtever you pick discover part of all & upload
2016-12-08 21:15:25 · answer #2 · answered by melgoza 4 · 0⤊ 0⤋
From -5 to 5 is 10 units.
From -4 to 4 is 8 units.
10 units X 8 units = 80 Square units
2007-11-13 13:57:34 · answer #3 · answered by Tim C 7 · 0⤊ 1⤋
I always thought the area of a rectangle was length x breath, and a triangle was length x breath divided by two? Am I wrong?
2007-11-13 13:58:15 · answer #4 · answered by wheeliebin 6 · 0⤊ 0⤋
lol. well according. to my calculations. i will tell you to not look at this answer. or study more.
2007-11-13 13:55:51 · answer #5 · answered by Guy 2 · 0⤊ 1⤋