Divide : 9ax² divided by 3a²x=?
14m²n divided by 7m²n²
2007-11-13 13:49:34 · 5 answers · asked by runningtoanguish 1 in Science & Mathematics ➔ Mathematics
3x/a
2/n
You kind of have to take each variable separately. In the first question, 9/3 = 3, a/a^2 = 1/a, x^2/x = x. Combine it all together, it's 3x/a.
2007-11-13 13:55:18 · answer #1 · answered by Pooty Pootwell 5 · 0⤊ 0⤋
9ax² / 3a²x
9ax² divided by 3a²x = 3
[the ax² cancel and 9 over 3 is 3]
14m²n / 7m²n²
14m²n divided by 7m²n² = 2/n
[the m² cancel]
[the n from the top cancels wit one at the bottom think of n² as n x n or two n's]
[14/7 is 2]
[the whole number always stays at the top and then there is a remaining n at the bottomso its 2/n
hope this helped
2007-11-13 22:00:31 · answer #2 · answered by MIMO 2 · 0⤊ 0⤋
Just cancel the matching terms:
9ax² / 3a²x = 3x/a
14m²n / 7m²n² = 2/n
2007-11-13 21:55:27 · answer #3 · answered by Robert S 7 · 0⤊ 0⤋
9ax² divided by 3a²x=?
3x/a
14m²n divided by 7m²n²
2/n
2007-11-13 21:55:44 · answer #4 · answered by Troy G 2 · 0⤊ 0⤋
9ax²/3a²x = 3x/a
14m²n/7m²n² = 2/n
2007-11-13 21:55:21 · answer #5 · answered by Wai Choong Shum 2 · 0⤊ 0⤋