PLEASE HELP, Height of rocket??

Question

How high does a rocket have to go above the
Earth's surface so that its weight is reduced
to 73.2% of its weight at the Earth's sur-
face? The radius of the Earth is 6380 km
and the universal gravitational constant is
6.67e-11 N *m^2/kg^2. Answer in units of
km.

Answer 1

Weight is reduced by 73.2% is when the gravitational force is reduced by 73.2%. F = (mass of the rocket * mass of the earth) *G/(distance between them)^2. Your initial distance was equal to the radius of the earth. calculate your new distance. Subtract 6380 000 m from the answer.