Linear Equations and Their Graphs?

Question

Graph using intercepts.

-3x = 6y - 2

I just need some examples of the x & y values that are possible (like x = 0, y = ?). I can't find a solution for the equation to do a graph.

I hope this makes sense at all...

Thanks firsthand.

Answer 1

Okay lets find the x-int. The definition of an x-int is the point where the line crosses the x-axis. So this means that the y-coordinate must be zero. So we set y as zero in the equation and solve for x.

-3x=6(0)-2
x=2/3

So our x-int is at (2/3,0)

We do the same for our y-int except we substitute 0 for x.

-3(0)=6y-2
1/3=y

So our y-int is at (0,1/3)

To graph, plot the points and draw a line that passes through both points.

Answer 2

We just did this in math last week and we have a test in it tomorrow.
Ok this is how you do it.
This is my notes on it.
x-int
Let y=0 and solve for x.
y-int
Let x=0 and solve for y.
x-intercept--where the graph crosses the x-axis (x,0)
y-intercept--where the graph crosses the y-axis (0,y)

-3x=6y-2
x-intercept
-3x=6(0)-2
-3x=-2
Divide be -3x here.
x=-2/-3
(-2/3,0)

y-intercept
-3x=6y-2
-3(0)=6y-2
6y-2
Here you would divide by 6.
y=-1/3
(0,-1/3)

I really hoped this helped. Sry it took me a while to solve it all but i hoped it helped.

Answer 3

well, first you should subtract 6y from both sides. then add 3x to both sides. this give you 6y= -2+3x then divde both sides by six. this will give you y=-2+3x/6. i did all that because in order to solve a linear equation, you need to have your equation in y equals format. then you can plug numbers in for x (some easy ones are 0,1,2 do at least 3 numbers) then you can solve for you. then graph it. if it makes a straight line, then you did it right. Good luck!

Answer 4

If x=0 then...
-3(0)=6y-2
0=6y-2
+2 +2
add two on both sides
2=6y
divide 6 on both sides
2/6=y (reduce)
1/3=y
USE the formula (X,Y)
y=1/3 and x=0

(0,1/3) the graph
hope that helps if it doesn't sorry.

Answer 5

y=mx+b bear in mind: you want in elementary terms 2 factors to allure to a line. first element you opt for to do until eventually now you graph is locate the intercepts and the slope. b is the y intercept and plug 0 for y and clean up for x you should get the x intercepts. you may end with the algebra right here given which you have already got 2 factors, so which you will draw a line with a ruler. yet, in case you opt for to easily look on the equation and graph it, first draw the y intercept(in elementary terms a element). that way you have already got one element. Then look on the slope and use upward thrust/run and use that element as a reference. so eg y=-5/4x+2 first element you will possibly do is placed a element on the y-axis whilst y is two. then, because of the fact the slope is damaging circulate down 5 and precise 4 and that's your 2nd element. If the slope replaced into constructive, then you definitely might circulate up 5 and precise 4. eg y=2x-10 First placed a element on y=-10. then because of the fact the slope is constructive, you circulate up 2 and precise a million. if slope replaced into damaging, then circulate down 2 and precise a million. desire i've got helped! this is not as demanding as curiously...believe me. you will get it!!

Answer 6

The instructions say to use the intercepts:

Let x=0 find y. mark the point (0,y) on the graph.

Let y=0 find x. mark the point (x,0) on the graph.

Draw a line through the 2 points then go on to the next question

Answer 7

Divide both sides by -3
You will be left with x= (6y - 2)/3
If y=0 then x=-2/3
I hope that helps

Answer 8

You need to set it up so Y = mX + b
so 6y = 3x -2
Go down on Y axis 2. put a point. then go 3 up. then one right then plot that point, so you should have 2 points then draw a line throught them