Mass percent?
Mass percent is grams of solute over liters of solution (hydrogen peroxide) i have 8.72g of h2o2
I know i have .46 moles in .00872 liters and the density is 1.00g/ml
what is the %m/m?
2007-11-13 12:08:37 · 2 answers · asked by mikala m 2 in Science & Mathematics ➔ Chemistry
Atomic weights: H=1 O=16 H2O2=34
Let the solution be called S.
0.46molH2O2/0.00872LS x 34gH2O2/1molH2O2 x 1LS/1000gS x 100% = 179% !!!
You miscopied something somewhere.
2007-11-13 12:23:39 · answer #1 · answered by steve_geo1 7 · 1⤊ 0⤋
M=mol/L 4.682M=mol/1L --> mol= 4.682 mol ethanol 4.682 mol ethanol x 40 six g ethanol/1mol = 215.37 g ethanol density= mass/quantity = 0.09677 g/mL = 967.7 g/L = mass/L mass = 967.7 g mass solvent = entire mass-mass ethanol = 967.7g - 215.37g = 752.3 g solvent (A) molality= mol answer/kg solvent = 4.682 mol/0.7523 kg = 6.22 mol/kg (B) mass % = mass ethanol/entire mass = (215.37 g/967.sixty seven g) x a hundred% = 22.3%
2017-01-05 10:53:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋