Zinc, Bromine, Chlorine.... It all sucked when "Moles" came up. Help, plz!?

Question

Yes, I can be a total dunce when it comes to moles, but I got every other problem except these three which threw me off.
1.) Calculate the mass of calcium oxide that will be formed when 0.48g of calcium is burned in 0.32g of oxygen. The equation is:
2Ca + O2 = 2CaO (Answer: 0.67g of CaO)
2.) Calculate the mass of zinc bromide that can be formed when 1.00g of zinc is mixed with 1.00g of bromine. The equation is:
Zn + Br2 = ZnBr2 (Answer: 1.41g of ZnBr2)
3.) What mass of sodium chloride would be expected of 0.460g of sodium with 0.426g of chlorine gas? The equation is:
2Na + Cl2 = 2NaCl (Answer: 0.702g of NaCl)
The answers are the "correct" answers listed on the answer sheet by the way. So, how did we get those? Help, plz! Thanx! I'd be lost without your intelligence lol

Answer 1

I will help you to solve one problem, and the rest would be solved by yourself in a similar way. OK?
1) The molar mass of Ca: 40.078 g/mol
The molar mass of O2: 31.999 g/mol
The molar mass of CaO: 56.077 g/mol
0.48g Ca is: (0.48g) /(40.078 g/mol) = 0.0120 mol Ca
0.32g O2 is: (0.32g) /(31.999 g/mol) = 0.01 mol O2.
Since 2 mol Ca reacts with 1 mol O2 in the reaction equation, 0.0120 mol Ca react with 0.0060 mol of O2. Ca is the limiting reactant, and thus 0.0120 mol CaO will be formed.
0.0120 mol CaO is: (0.0120mol)*(56.077 g/mol) = 0.67g
Thus 0.67g of CaO is to be formed theoretically.

You now should be able to solve (2) and (3).