Math problem. Help anyone????

Question

my daughter who is in 5th grade has this math problem . I have no clue. Here it goes: If you start with 3 and count by 7's you get the terms of the sequence 3, 10, 17,...528 where 3 is the 1st term, 10 is the 2nd term , 17 is the 3rd term, and so forth up to 528 with is the Nth term . What is the value of N?

Are you smarter than a 5th grader!!!!!!

Answer 1

This is definitely not 5th grade math except your daughter is in a gifted class .
Anyway here goes:

This problem falls under arithemetic progression series and the formula is:
a + (n-1)d = Nth term.

a is the first term which is 3
n is the term number(which is what we hope to find)
d is the common difference which is 7
and Nth term is 528.

Just plug the values in:
3 + (n-1)7 = 528.

subtract 3 from both sides of the equation to give:

(n+1)7 = 525

divide both sides by 7 to give:
n+1 = 75

add 1 to both sides to give:

n = 76

Answer 2

Hello,

There is a formula that states an = a1 + (n-1)d where an is the nth term, a1 is the first term, n is the number of the term and d is the difference between each term so.

an is the 528, a1 = 3 and d = 7 giving us.

528 = 3 + (n-1)*7 or subtracting 3 from both sides we have

525 = (n-1)*7 now divide by 7 and we have 75 = n-1 then add 1 to both sides giving us n = 76

Checking 3 + (76 -1)*7 = 3 + 525 = 528

Am I smarter than a fifth grader??

Hope This Helps!.

Answer 3

They're starting on 3 and adding 7. They want to know how many 7's do you have to add to 3 to get 528. First of all if you take away 3 from 528 you get how many sevens do you add to zero to get 525 (528 - 3), so basically, how many sevens are in 525? Divide 7 into it and you get 75. But seeing as they count 3 as the first term we have to add that on.

Ans: N = 76 (I think lol!!)