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I am given a torque vs. time graph which starts at (0,0), increases linearly to (4,0.2), then down to (10,-0.1), then back up to (12,0). The question is, a 12-cm-diameter, 4cm-thick, 2.0 kg disk, which is initally at rest, experiences the net torque shown in the graph (described above). What is the disk's angular velocity at t = 12s? Please help!

2007-11-13 11:01:37 · 1 answers · asked by sean77771 1 in Science & Mathematics Physics

1 answers

Torque = I*deltaOmega/delta t
Omega is angular velocity
I is moment of inertia (calculate it for the disk)
Angular velocity is the area under the graph times I

Torque to angular velocity is related the same way as force is related to linear velocity.

2007-11-13 14:28:16 · answer #1 · answered by Snowflake 7 · 0 0

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