calculus problem?

Question

The table gives values for functions f and g, and their derivatives. Determine the given derivatives and
write down the formulas used.
the |' are not absolute values they are to divide each number like a table
x |0 | 1 | 2
f(x) | 5 | −1 | 4
g(x) | 2 | 2 | 0
f'(x) |−2 | 2 | 3
g'(x) | 5 | 6 | 0.5

(b)If H(x) = f(g(x)) then H'(1) = ? -24 i got it from chain rule 2(2)(-1)(6)

(c)If F(x) = e^(f(x)) then F'(1) = ? 0
(d)If G(x) = (f(x))^2 then G'(1) = ? -4 is it 2(-1)(2)
(e)If K(x) = sin (g(x)) then K'(2) = ? .5 i got it from sin(4)cos.5 because of chain rule

Answer 1

(b) H'(x) = f'(g(x)) * g'(x) so

H'(1) = f'(g(1)) * g'(1) = f'(2) *g'(1) = 3*6 = 18

(c) F'(x) = d/dx(e^g(x)) = e^(g(x)) * g'(x) so

F'(1) = e^(g(1)) * g'(1) = (e^2)(6) = 6e²

(d) Your answer is correct.

(e) d/dx (sin(g(x)) = cos(g(x)) * g'(x) so

K'(2) = cos(g(2)) * g'(2) = cos(0) * 0.5 = 0.5

You got the right answer, but I don't see how you got it from sin(4) cos(0.5)