all the 2's in this column its a small two. (square)
I
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I
a) x2-9x+14
b) x2+6x-16
c) x2-9x+20
d) x2-7x+12
e) y2-9y-10
f) a2+5a-24
2007-11-13 08:56:58 · 4 answers · asked by Linda-chica 1 in Science & Mathematics ➔ Mathematics
(x-2)(x-7)
(x+8)(x-2)
(x-4)(x-5)
(x-3)(x-4)
(y-10)(y+1)
(a+8)(a-3)
2007-11-13 09:11:41 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Here's a tip:
With the last number, write down all the numbers that multiply to make that number, including negatives.
Secondly, add each group together, until you create the second term. Then plug those numbers into your parenthesis.
Ex. for a) 14 = 14 x 1, -14 x -1, 7 X 2 , -7 X -2
14 + 1 = 15
-14+ - 1 = -15
7+2=9
-7 + -2 = -9 <-----
You've found both factors
x^2 - 9X + 14 = (x-9)(x-2)
Also, look up the quadratic formula, it's the method designed to solve these types of problems. Good luck!
2007-11-13 09:10:25 · answer #2 · answered by canaricide 1 · 0⤊ 0⤋
i'll do one, but you must do the rest:
x^2-9x+14 = (x-2)(x-7), notice that -2 times -7 equals the origional 14 and that -2 and -7 add up to the origional -9, try the rest.
2007-11-13 09:04:16 · answer #3 · answered by luisfernu@sbcglobal.net 2 · 0⤊ 0⤋
You are never going to learn how to do this if you depend on other to people to do it for you. This will only lead to difficulty in later math classes.
2007-11-13 09:00:58 · answer #4 · answered by Elizabeth P 3 · 0⤊ 0⤋