What is the probability that their numbers are all greater than 25?
a. 1/8
b. 23/196
c. 69/625
d. 1/2
2007-11-13 08:08:24 · 11 answers · asked by Hollywood614 2 in Science & Mathematics ➔ Mathematics
there are twenty-five tickets that are greater than 25, staring from 26 to 50.
so the the probablity of picking the first ticket that is greater than 25 is 25/50
since there is no replacement, there are 49 tickets left, out of which 24 tickets are greater than 25. So that gives you the probablity that the second ticket is greater than 25 is 24/49. And the probability that the third ticket are greater than 25 is 23/48
P = 25/50 * 24/49 * 23/48
P = 23/196 <== answer
2007-11-13 08:17:26 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The answer is B, and here's why.
To start with, you have 50 tickets, and 25 of them ar over 25, so your odds of pulling a high ticket on the first pull are 25:50, or 1:2.
Now on the second pull there are 49 tickets left and 24 high ones (because you already pulledf a high one. Your odd on the second pull are 24:49, and combining that with the odds of the first pull, your odds of pulling two straight high numbers is 24/98.
The third pull has 48 tickets left and 23 of them are higher than 25, so your odds here are 23:48, which when combined with the other two pulls, makes your total odds 552:4704, which simplifies down to 23/196.
2007-11-13 08:19:29 · answer #2 · answered by Expat Mike 7 · 0⤊ 0⤋
B
25/50 X 24/49 X 23/48 = 23/196
2007-11-13 08:16:25 · answer #3 · answered by Tim C 7 · 3⤊ 0⤋
You have a 25/50 chance of the first one being over 25, multiplied by a 24/49 chance of the second one being over 25, multiplied by a 23/48 chance of the third number being over 25. This will give you a large fraction that you simplify by dividing both the numerator and the denominator by the same factor.
2007-11-13 08:37:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The first has 25/50 chance, if it is then the second has 24/49 chance, and if that is too then the third has 23/48 chance. Multiply those together and you get 13800/117600, which simplifies to 23/196, which is B. So Tim C got it right. All these C people just don't know their math, I guess.
2007-11-13 08:17:04 · answer #5 · answered by Anonymous · 1⤊ 0⤋
1/2
2007-11-13 08:12:23 · answer #6 · answered by jcksvg 2 · 0⤊ 4⤋
okay so you have 50 numbers. In each draw the probability of getting a number between 25-50 is 1/2. okay so since it is three drawings you would multiply 1/2 X 1/2 X 1/2 which is 1/8. I hope that helps!
2007-11-13 08:14:50 · answer #7 · answered by gymnast8517 2 · 0⤊ 4⤋
first get the chances out of 50 (27/50). Then mutiply 50 and 28 by the same number and find out which option matches both of the numbers. (?). with this formula (the one i believe is correct) there is no correct answer
2016-04-03 23:13:07 · answer #8 · answered by Anonymous · 0⤊ 0⤋
there are C(50,3) = 19600 possible draws of 3 tickets
there are C(25,3) = 2300 draws of 26 through 50
2300/19600 = 23/196
B.
2007-11-13 08:17:45 · answer #9 · answered by holdm 7 · 0⤊ 0⤋
c
2007-11-13 08:14:39 · answer #10 · answered by Anonymous · 0⤊ 4⤋