please help math question??? dealing with equations...?

Question

could someone please solve this and give me an explanation... thanks sooo much,

9-(2k-3)=k

Answer 1

Subtract 9 from both sides.
-(2k-3)=k-9
Distribute the "-1" on the left side of the equation.
-2k+3=k-9
Subtract 3 from both sides.
-2k=k-12
Subtract k from both sides.
-3k=-12
Divide both sides by -3.
k=4

Answer 2

You're being asked to distribute the negative thru the whole deal and then solve.

9-(2k-3) =k

9 -2k +3 (now + as a negative minus a neg is the same as
+ a positive)

9-2k+3=K
-2k +12=K
12=3K
4=K

Answer 3

9-(2k-3)=k
first distribute, if there is nothing in front of the parentheses except for a negative sign then you multiply by -1
9-2k+3=k
then combine like terms
12-2k=k
put all the "k's" on one side of the equation
+2k +2k
12=3k
then divide by 3 on both sides
4=k

Answer 4

9-(2k-3)=k
9 = k + 2k - 3
9 + 3 = 3k
3k = 12
k = 4

Answer 5

isolate k.

first distribute the - sign.

9-2k+3=k

isolate k

6-2k=k

-3k=-6 (change signs when switching sides)
-k=-6/-3
k=2

Answer 6

9-(2k-3)=k
9-3+2k=k
6+2k