Please help me to explain how to completely factor the following polynomial. 4x3 - 24x2 + 32x.
2007-11-13 07:20:13 · 5 answers · asked by Michele 1 in Science & Mathematics ➔ Mathematics
I would start by factoring out a 4 and an x from each term as they all have that in common:
4x*(x^2-6x+8) Then factor what is in the parenthesis:
(x^2-6x+8)=(x-4)(x-2)
So the full factorization is 4x(x-4)(x-2).
2007-11-13 07:24:09 · answer #1 · answered by Trevor H 3 · 0⤊ 0⤋
I would notice that all the terms have an X and divisible by 4.
4x³- 24x² + 32x = 0 becomes 4x [x²- 6x + 8] =0
4x (x -2) (x -4) = 0
x = 2
x = 4
x = 0
2007-11-13 15:34:34 · answer #2 · answered by ? 3 · 0⤊ 0⤋
First take out a g.c.f. of "4x"
(4x)(x^2-6x+8)
Then factor the quadratic, find two numbers that add to -6, and mulptiply to get +8
(4x)(x-4)(x-2)
2007-11-13 15:24:28 · answer #3 · answered by aaron.brake 3 · 0⤊ 0⤋
= 4x( x^2 - 6x +8) = 4x(x-2)(x-4)
2007-11-13 15:24:46 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Try myalgebra.com!!
2007-11-13 15:26:56 · answer #5 · answered by jjsp 1 · 0⤊ 0⤋