The perimeter of a rectangle is 96 inches. The legnth of the rectangle is 6 inches less than twice the width. Find the dimensions of the rectangle.
2007-11-13 07:11:14 · 6 answers · asked by Brandon 1 in Science & Mathematics ➔ Mathematics
if the width is x, then the length is 2x - 6
P = 2 (Width + Length)
given the perimeter is 96
96 = 2 (x + 2x - 6)
48 = 3x - 6
54 = 3x
x = 18
width: 18in
length: 2(18) - 6 = 30in
2007-11-13 07:15:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let the length be l and width be w
l = 2w - 6
2l + 2w = 96
or l + w = 48
Substitile 2w - 6 for l
2w - 6 + w = 48
3w - 6 = 48
3w = 54
w = 18
Since l = 2w - 6, l = 2(18) - 6 = 30
Width is 18
Length is 30
CHECK:
Perimeter = 18 + 18 + 30 + 30 = 96
2w - 6 = 2(18) - 6 = 30
2007-11-13 15:17:44 · answer #2 · answered by PeterT 5 · 0⤊ 0⤋
p=2l+2w is the equation because in a rectangle the opposite sides of a rectangle equal eachother
from your word problem, l=2w-6
substitute this into the equation as follows
96= 2 (2w-6) + 2w
96 = 4w-12+2w
96 = 6w-12
108 = 6w
w = 18
since l = 2w-6 we can plug l in to get
l = 2(18) - 6
l = 30
96 = 2(30) + 2(18)
2007-11-13 15:22:29 · answer #3 · answered by Elizabeth P 3 · 0⤊ 0⤋
30" by 18"
2007-11-13 15:19:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x = width
2x-6 = length
P = 6x-12 = 96
6x = 108
x = 18 = width
2(18)-6 = 30 = length
2007-11-13 15:19:34 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
length=30inches
width=18 inches
2007-11-13 15:16:55 · answer #6 · answered by Trevor H 3 · 0⤊ 0⤋