Law of sines?

Question

Here is the problem:
http://i9.tinypic.com/854smc3.gif

a. 454.90'
b. 359.73'
c. 227.45'
d. 719.46'

Thanks for the help!

Answer 1

first find angle a = 180 - 73 39 - 37.21 = 69
then use sine rule to find length of ab

ab / sin 37 21 = 700 / sin 69
then am is 1/2 ab = 700 * sin 37 21/2/sin69
= 227.45 (ans. c)

Answer 2

We're given side a and angles B and C

In a triangle the sum of the angles is 180 so
A + B + C = 180º
or
A = 180º - (B + C) = 180º - (73º 39` + 37º 21') = 180º - 111º = 69º

By the law of sines
a/sin A = b/sin B = c/sin C
Side AB is also c

a/sin A = c/sin C
c = a sin C / sin A
= 700 * sin (37º 21`)/ sin(69º)
= 700 * 0.606682351002 / 0.9335804264972
= 454.891334102614

But we now need half that as AM is one half of AB
454.891334102614 / 2 = 227.445667051307

Amswer c

Answer 3

What do they mean by the middle point of AB (in caps)?
angle a is 69.5
side b=716.14
side c=451.93