I forgot to mention, both cars are traveling in the same direction. I did very well in Algebra (20 years ago), I just can't remember for the life of me how to set this up. I appreciate anyone's time!!!!!
2007-11-13 04:51:39 · 9 answers · asked by Jeff 1 in Science & Mathematics ➔ Mathematics
Relative speed is 15 mph
t = d / s
t = 1 / 15 h
t = 4 min
2007-11-13 04:56:16 · answer #1 · answered by Como 7 · 2⤊ 1⤋
find the relative velocity of the cars:
Vrel = Vfast - Vslow = 55 mph - 40 mph = 15 mph
Now, the fast car has to travel 1 mile at a speed of 15 mph to catch up to the slow car.
using distance = rate * Time
Time = distance / rate
Time = 1 mile / 15 miles/hour = .0666666666666 hours
Answer: 4 minutes or 240 seconds
2007-11-13 05:02:10 · answer #2 · answered by KEYNARDO 5 · 0⤊ 1⤋
No problem, the only question I have is are you asking for how great a distance it is before the second car catches up, or how long time wise?
Time wise is the easier question, first you find the difference of the speeds to get relative speed, so
55-40=15mph difference
then we plug that velocity into our generic distance=velocity*time and rearange to get t=d/v
t=1/15=1/15 of an hour or 4 minutes
Now we use that time to get how far it will take before they are even and I will do this relative to how far the first car must go,
distance = velocity*time=40*1/15=2&2/3 miles from where the first car starts
2007-11-13 05:00:44 · answer #3 · answered by Mic K 4 · 0⤊ 1⤋
Since the difference in speed is 15 mph, dividing 15 by 60 to get miles per minute yield 1/4 mpm. Therefore, 4 minutes.
2007-11-13 04:58:11 · answer #4 · answered by Spartacus! 7 · 0⤊ 1⤋
. Number of coins x Value of Each = Total of Value Nickels y .05 .05y Dimes 81-y .10 10 (81-y) .05y+810-.10y=570 y= 48 81- 48= Taylin has 33 dimes Rate (m/hr) Time (hr) Distance Car 1 55mph x 180 miles Car 2 65mph x 180 miles 55x +65x = 180 miles 120x =180miles x = 1.5
2016-05-22 23:34:36 · answer #5 · answered by ? 3 · 0⤊ 0⤋
15 miles (faster) is to 60 as 1 is to X
15 / 60 =1 / x
60 = 15 X
X = 4 minutes
2007-11-13 04:57:38 · answer #6 · answered by Mencken 5 · 0⤊ 1⤋
40t = distance the slower car has traveled
55t = distance the faster car has traveled
40t + 1 = 55t
t = (1/15) hr = 4 min
2007-11-13 04:56:13 · answer #7 · answered by DWRead 7 · 0⤊ 1⤋
15 meters apart
60 mins or 1hr
= 60 mins / 15 meters
= 4 mins
2007-11-13 05:07:55 · answer #8 · answered by ryukansentsumuji01 2 · 0⤊ 1⤋
240 sec
2007-11-13 05:23:27 · answer #9 · answered by Anonymous · 0⤊ 1⤋