its math..
2007-11-13 03:25:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(2g+9)(g+1)
(2e-7)(3e+1)
(r +4)(5r-2)
If you need to find the values then set all the () equal to 0
2g+9 = 0 and g + 1 = 0
2g = -9 and g = -1
g = -9/2 and g = -1
2e-7 = 0 and 3e + 1 = 0
2e = 7 and 3e = -1
e = 7/2 and e = -1/3
r + 4 = 0 and 5r -2 = 0
r = -4 and 5r = 2
r = -4 and r = 2/5
2007-11-13 03:29:34 · answer #1 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
(2g+9)(g+1)
g=9/2 or -1
6e^2-19e-7
(2e-7)(3e+1)
e=7/2 or-1/3
5r^2+18r-8
(5r+2)(r-4)
r=-2/5 or 4
2007-11-13 03:32:48 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Use quadratic formula to solve,or factor assuming these are equations equal to zero.
2007-11-13 03:32:48 · answer #3 · answered by dwinbaycity 5 · 0⤊ 0⤋
(2g+9)(g+1)
(3e+1)(2e-7)
(5r-2)(r+4)
2007-11-13 03:32:34 · answer #4 · answered by someone else 7 · 0⤊ 0⤋
If those are equations, then where is the equal sign?
2007-11-13 03:32:23 · answer #5 · answered by morningfoxnorth 6 · 0⤊ 0⤋