Alright, I'm having some trouble figuring out these slopes...
My first question is, would 7x + 6(x + 5y) = 6x + y be linear? If so, how would I right it in standard form?
My second question is, what is the slope that passes through (-1, -1) and (10,9)?
2007-11-13 03:02:25 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
For the first one, you just have to simplify the equation. It WILL be linear because both x and y are only first powers.
7x + 6(x+5y) = 6x + y
7x + 6x + 30y = 6x+y
7x=-29y
-(7/29) x = y
The slope is -7/29, and the y intercept is 0.
For the second one use the equation m=(y2-y1)/(x2-x1) to find the slope.
2007-11-13 03:08:31 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
Standard form of a line is
Ax + By = C
so simplify the equation to combine all x terms and all y terms.
7x + 6x + 30y = 6x + y
7x + 29y = 0
For finding slope, use the formula:
m = (y2 - y1) / (x2 - x1)
Just be careful to be consistent in which point you subtract from which, and watch your signs!
m = [9 - (-1)] / [10 - (-1)]
= 10/11
2007-11-13 11:35:42 · answer #2 · answered by chcandles 4 · 0⤊ 0⤋
7x+6(x+5y)=6x+y is linear because it is of first degree in x. No square term etc.
7x+6x+30y=6x+y
29y=-7x
y=(-7/29)x is the standard form.
slope = (y2-y1) /(x2-x1)
x1=-1 y1=-1 x2=10 y2=9
slope=(9-(-1)) / (10-(-1)) = 10/11
2007-11-13 11:10:52 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋