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In the Lewis-Dot structure of NF, would N double bond to F?

2007-11-13 02:49:34 · 4 answers · asked by Ashley 2 in Science & Mathematics Chemistry

4 answers

No, F will not form a double bond. Because F is a very small halogen, at most it will form a single covalent bond.

2007-11-13 02:57:10 · answer #1 · answered by hcbiochem 7 · 0 0

You might have been led astray by a wrong formula. NF does not exist. There is a N2F2, where the empirical formula is NF, but no molecular compound with the formula NF exists.

As said above, NF3 contains only single bonds.

2007-11-13 11:03:40 · answer #2 · answered by ChemTeam 7 · 0 0

No, N will not form double bond with F. This is bcoz F is in period 2. Therefore, the maximum valence electrons which F can hold is only 8. The electronic configuration of F is 1s2 2s2 2p5.
It cannot expands its valency as it does not have vacant orbitals. Hence, F only can form single bond with N.

2007-11-13 11:02:08 · answer #3 · answered by Anonymous · 0 0

In Nitrogen Trifluoride, bondings are single type not double type:
      ..
F : N : F
      ..
      F

the pair of dots above the nitrogen atom are two available electrons

2007-11-13 10:56:57 · answer #4 · answered by CHESSLARUS 7 · 0 0

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