.......... When its speed is 15 m/s, how far has it traveled?
2007-11-13 02:15:59 · 3 answers · asked by Rele007 1 in Science & Mathematics ➔ Physics
Use the formula
2ax = Vf ² - Vi ²
where:
a = acceleration
x = displacement
Vf = final velocity
Vi = initial velocity
Solution:
2ax = Vf ² - Vi ²
2(2m/s²) (x) = (15 m/s)² - ( 5m/s)²
4x = 225 - 25
x = 200/4
x = 50 meters
2007-11-13 02:27:39 · answer #1 · answered by rene c 4 · 0⤊ 0⤋
What will its average velocity have been at that time?
How long will the conditions will have been in effect, or how long will it take to reach 15m/s?
Multiply the two numbers together.
Constant accelerations make it easy.
2007-11-13 02:25:53 · answer #2 · answered by Tom K 6 · 0⤊ 0⤋
v=final velocity=15
u=initial velocity=5
a=acceleration=2
S=distance travelled
(v*v)-(u*u)=2*a*S
(15*15)-(5*5)=2*2*S
225-25=4*S
200=4*S
S=200/4
S=50
DISTANCE TRAVELLED=50 metre
2007-11-13 02:42:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋