Write the function f(x) = -5x^2 - 60x - 181 in vertex form, and identify its vertex.?

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Write the function f(x) = -5x^2 - 60x - 181 in vertex form, and identify its vertex.?

2007-11-13 01:54:52 · 3 answers · asked by md_free23 1 in Science & Mathematics ➔ Mathematics

3 answers

f ( x ) = ( - 5 ) ( x ² + 12 x ) - 181
f ( x ) = ( - 5 ) ( x ² + 12x + 36 - 36 ) - 181
f ( x ) = ( - 5 ) ( x ² + 12x + 36 ) + 180 - 181
f ( x ) = ( - 5 ) (x + 6) ² - 1
Vertex (- 6 , -1)

2007-11-13 05:29:58 · answer #1 · answered by Como 7 · 2⤊ 1⤋

f(x) = -5xÂ² - 60x – 181 = -5(xÂ²+12x+36) – 1 = -5(x+6)Â² – 1

The vertex of the parabola is (-6, -1).

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2007-11-13 12:28:30 · answer #2 · answered by oregfiu 7 · 0⤊ 2⤋

f(x) = -5(x - 6)^2 + 361 shows that the vertex is (-6,361).

2007-11-13 12:17:37 · answer #3 · answered by Tony 7 · 0⤊ 2⤋