tricky alegbra question please help me!!!! worth 10 points?

Question

http://i40.photobucket.com/albums/e215/xxs3xp1stolxx/Algebra%20II/411q/Picture1.png
1. -4Q
2. L - 3P
3. RS
4. N - M
5. N + T

Answer 1

1.
Its a matrix multiplied by a constant, so simply multiply each element of the matrix by -4. The resulting matrix is:

-4Q = [-8 -12 8]

2.
Simply subtract the elements of the matrix 3P from their corrosponding elements in matrix L.

3.
When you multiply matrices, you go through and take the first column of matrix S, make it a horizontal matrix, and multiply each element to its corrosponding element in the first row of the matrix R. Repeat, by first 'exhausing' the columns of matrix S, to get the result:

RS=
[0 0 -12]
[4 4 15 ]

4.
Simply subtract each element of M from its corrosponding element in N.

5. This is an invalid matrix operation since the size of matrix N is not the same as matrix T.

Answer 2

take a row of the first matrix.
then take a colon of the second matrix

multiply corresponding elements, find the sum
This sum will be an element

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