A woman is 1.8 m tall and has a mass of 60 kg. She moves past an observer with the direction of the motion parallel to her height. The observer measures her relativistic momentum to have a magnitude of 2.0 1010 kg·m/s. What does the observer measure for her height? Help please??
2007-11-11 18:34:18 · 4 answers · asked by darkangel_0219 1 in Science & Mathematics ➔ Physics
height in meters
2007-11-11 18:40:17 · update #1
The relativistic momentum is
p = K*m0*v, where K= 1/√[1-v^2/c^2]; (my keyboard has no gamma symbol, which is usually used for this quantity)
K = p / (m0*v) you can solve for v from this.
EDIT: I have worked it out here http://img204.imageshack.us/img204/7574/relativisticmomentumgx0.png
The observed length is Lo = L0/K
Lo = L0*m0*v / p
EDIT: for p = 2*10^10, you should get 1.24 m
2007-11-11 19:42:57 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
divide the relativistic momentum by her mass to get the relativistic velocity. Now solve for gamma. (1/sqrt(1-v^2/c^2)) using the velocity you just solved for. Then length proper is 1.8m. So, L= length proper / gamma.
But from the looks of the momentum, she will NOT be traveling at a relativistic speed (v>.1c). I see it as 2.01010 but I assume that is supposed to be 201,010 which would work but you would get an answer like L=1.799999999998 meters.
2007-11-12 03:37:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
in pounds and in feet???
2007-11-12 02:37:14 · answer #3 · answered by pe pe 2 · 0⤊ 0⤋
YUCK YUCK -N-YUCK
2007-11-12 02:38:15 · answer #4 · answered by Cheeta 2 · 0⤊ 0⤋