3x^2 - 2x = 0
x(3x-2)=0
x=0 or 3x-2 = 0
x=0 or 3x = 2
x=0 or x = 2/3
2007-11-11 16:58:10
·
answer #1
·
answered by Kenneth Koh 5
·
2⤊
1⤋
First find the common factor which is x, then you'll have.
x(3x-2)=0
Now have all the parts of the equation equal 0, so
x=0
and
3x-2=0
3x=2
x=2/3
So, x=0 and x=2/3
2007-11-12 00:54:46
·
answer #2
·
answered by YamiRob 2
·
0⤊
1⤋
x(3x - 2)=0
3x - 2 = 0 and x = 0
3x = 2
x = 2/3
2007-11-12 00:51:48
·
answer #3
·
answered by Ms. Exxclusive 5
·
1⤊
1⤋
First, isolate the variable x.
Then solve for x.
x = 0 and x=2/3
2007-11-12 00:57:29
·
answer #4
·
answered by mzhudson@sbcglobal.net 5
·
0⤊
1⤋
factor out "x"
that will be:
x(3x - 2) = o
then get the values of "x"
x = 2/3 <=== from (3x - 2)
and
x = 0
2007-11-12 00:53:56
·
answer #5
·
answered by windzard 2
·
1⤊
1⤋
(x) (3x - 2) = 0
x = 0 , x = 2 / 3
2007-11-12 11:30:02
·
answer #6
·
answered by Como 7
·
0⤊
1⤋
take x out..
x(3x-2)=0
x=0, 2/3
2007-11-12 00:52:11
·
answer #7
·
answered by ejay 2
·
0⤊
2⤋
You can factor is as the other answers show or use the quadratic formula. Your choice!
2007-11-12 00:54:12
·
answer #8
·
answered by Mark P 2
·
0⤊
1⤋
I HAVE NO IDEA!!!!!!!!!!!!SORRY
2007-11-12 00:52:24
·
answer #9
·
answered by Belen B 1
·
1⤊
1⤋