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At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 35 mi/hr. Two hours later, a second truck leaves along the same route, travelling at 70 mi/hr. When will the second truck catch up to the first?

2007-11-11 16:48:04 · 3 answers · asked by christatsotaddle 2 in Science & Mathematics Mathematics

3 answers

1:00 p.m.
If you want to know how to solve it:
35 mi/hr * x hrs has to equal 70 mi / hr * (x-2) hrs
35x = 70*(x-2)
35x = 70x - 140
35x = 140
x = 4 hrs where x is the number of hours traveled after 9:00 a.m.
Any other questions?

2007-11-11 16:57:39 · answer #1 · answered by Mark P 2 · 1 0

Truck A
35 miles / hour
Travels 70 miles in 2 hours

Truck B
70 miles / hour

Relative speed of B to A is 35 miles/ hour (A assumed at rest)

time = 70 / 35 hours = 2 hours

Will catch up after 2 hours

2007-11-12 12:15:16 · answer #2 · answered by Como 7 · 0 1

70t = 35(t + 2)
=> 35t = 70
=> t = 2
after 2 hrs of its start at 1.00 p.m.

2007-11-12 00:58:12 · answer #3 · answered by sv 7 · 0 0

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