solve for all the zero's showing all work
2007-11-11 15:57:58 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Solve for x.
x^6 + 3x^4 - 49x^2 + 45 = 0
(x² - 1)(x^4 + 4x² - 45) = 0
(x + 1)(x - 1)(x² - 5)(x² + 9) = 0
(x + 1)(x - 1)(x + √5)(x - √5)(x² + 9) = 0
(x + 1)(x - 1)(x + √5)(x - √5)(x + 3i)(x - 3i) = 0
x = ±1, ±√5, ±3i
2007-11-11 16:05:18 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
Solve for x.
x^6 + 3x^4 - 49x^2 + 45 = 0
(x² - 1)(x^4 + 4x² - 45) = 0
(x + 1)(x - 1)(x² + 9)(x² - 5) = 0
(x + 1)(x - 1)(x² + 9)(x + √5)(x - √5) = 0
(x + 1)(x - 1)(x + √5)(x - √5)(x² + 9) = 0
(x + 1)(x - 1)(x + √5)(x - √5)(x + 3i)(x - 3i) = 0
x = ±1, ±√5, ±3i
36 seconds ago
2007-11-11 16:06:38 · answer #2 · answered by ? 1 · 0⤊ 1⤋
I suggest u graph it
There are 4 solutions for x.Here are they.
x=-2.2361 , x=-1 , x=1 , x=2.2361 ,
2007-11-11 16:43:52 · answer #3 · answered by Kenneth Koh 5 · 0⤊ 0⤋