Solve. (Square root 4x+8)-4=0
2007-11-11 14:34:06 · 5 answers · asked by too_b2000 1 in Science & Mathematics ➔ Mathematics
Move the 4 over and square both sides.
√(4x +8) -4 = 0
√4x + 8 = 4
4x + 8 = 16
4x = 8
x = 2
2007-11-11 14:39:07 · answer #1 · answered by aaron.brake 3 · 0⤊ 0⤋
Solve. (Square root 4x+8)-4=0
â(4x + 8) = 4
Squaring both sides:
4x + 8 = 16
4x = 16 - 8 = 8
x = 8/4 = 2
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2007-11-11 14:41:07 · answer #2 · answered by Joymash 6 · 0⤊ 0⤋
add 4 to both sides: (Square root 4x+8) = 4
square both sides: 4x+8 = 16
subtract 8 from both sides: 4x = 8
divide by 4: x = 2
2007-11-11 14:39:32 · answer #3 · answered by Cyali 3 · 0⤊ 0⤋
â(4x+8) - 4 = 0
â(4x+8) = 4
4x + 8 = 16
4x = 8
x = 2
2007-11-11 14:39:32 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
since i know that this is ur homework and that u should do it by urself, i'll only give a hint, then u hv to solve it by urself.
4x+8=16
2007-11-11 14:45:48 · answer #5 · answered by gaby_p 2 · 0⤊ 0⤋