Need Help. Can anyone help me. PLZ?

Question

Well i jsut did an experiment where i heated copper sulfate then i weighted the contents.

Here are my observations:

mass of crucible + lid= 20.144g
mass of crucible + lid+ copper sulfate = 23.827g
mass of copper sulfate 3.689
mass of crucible + lid+ contents= 22.577g

I need to find the mass of the hydrate used.

Calculate the mass of water of hydration lost.

and calclate the mass of dehydrated salt remaining (CuSO4)


Can anyone help me on these 3 problems. Can anyone help me out?

Anyone?????

Answer 1

I think you are just confused by the way the question is worded.

The "hydrate" IS just copper sulfate hydrate, 3.689 g

Mass of water lost = 23.827 g - 22.577 g

The dehydrated salt is the contents at end, so its mass is the last weighing (crucible + lid + contents) less the first weighing (crucible + lid).