if the problem is
x^-2y^-12/x^-6y^-2, would you have to simplify it first or switch it--- x^6y^2/x^2y^12
2007-11-11 13:43:03 · 8 answers · asked by wingman 1 in Science & Mathematics ➔ Mathematics
Simplify. You subtract exponents when it is a division problem.
x^-2 and x^-6 = x^4
y^-12 and y^-2 = y^-10
answer: x^4/y^10
2007-11-11 13:50:23 · answer #1 · answered by deirdrezz 6 · 0⤊ 0⤋
I'd switch it first...then simplify making the answer x^4/y^10
2007-11-11 21:46:19 · answer #2 · answered by PUgrad05 2 · 0⤊ 0⤋
You can do it in either order you will still get the same answer which is x^4/y^10
2007-11-11 21:47:22 · answer #3 · answered by Me 1 · 0⤊ 0⤋
(x^-2y^-12)/(x^-6y^-2)
= x^-2y^-2(y^-10)/x^-2y^-2(x^-4)
= y^-10/x^-4
= x^4y^-10 answer.
2007-11-11 21:52:26 · answer #4 · answered by sv 7 · 0⤊ 0⤋
Yes.pp
2007-11-11 21:45:46 · answer #5 · answered by ttpawpaw 7 · 0⤊ 0⤋
simplify
2007-11-11 21:46:40 · answer #6 · answered by razzle dazzle 2 · 0⤊ 0⤋
?
Wait tell you forget all that stuff!!
2007-11-11 21:49:15 · answer #7 · answered by M 3 · 0⤊ 0⤋
WTF???
2007-11-11 21:48:21 · answer #8 · answered by Anonymous · 0⤊ 0⤋