Simplify m^-1 + z^-1 / m^-1 - z ^-1?

0 ⤊

Simplify m^-1 + z^-1 / m^-1 - z ^-1?

2007-11-11 12:17:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

[06]
m^-1+z^-1
=1/m +1/z
=(m+z)/mz
similarly m^-1 -z^-1
=1/m -1/z
=(z-m)/mz
Therefore given expression
=(m+z)/mz * mz/(z-m)
=(m+z)/(z-m)
=(m+z)/-(m-z)
= -(m+z)/(m-z)

2007-11-11 12:26:02 · answer #1 · answered by alpha 7 · 0⤊ 0⤋

Please learn to use parentheses.

I assume you mean

(m^-1 + z^-1) / (m^-1 - z ^-1)

= (1/m + 1/z) / (1/m - 1/z)

Multiply numerator and denominator by mz.

= (z + m) / (z - m)

2007-11-11 20:22:21 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋

m^-1=1/m ; z^-1=1/z
1/m+1/z=(m+z)/mz
1/m-1/z=(z-m)/mz
m^-1+z^-1/m^-1-z^-1=(z+m)/(z-m)

2007-11-11 20:25:11 · answer #3 · answered by Dick 1 · 0⤊ 0⤋

wait, I think it might be 0

2007-11-11 20:20:34 · answer #4 · answered by ImUURU? 3 · 0⤊ 2⤋