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2 answers

In a 45-45-90 triangle sin 45=cos 45 = sqrt(2)/2
sin (22.5) = sin(45/2) = +/- sqrt((1-cos45)/2)
So sin(22.5) = +/-sqrt((1-sqrt(2)/2)/2)
Now 67.5 degrees = 90 - 22.5 degrees
So cos (67.5) = sin (22.5)
So answer is 8(1-sqrt(2)/2)

2007-11-11 12:29:05 · answer #1 · answered by ironduke8159 7 · 0 0

cos(a)sin(b)=1/2(sin(a+b)-sin(a-b))

4(sin(90)-sin(45))=4(1-√2/2)

2007-11-11 12:13:32 · answer #2 · answered by norman 7 · 0 0

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