7r-5s=1
5r+7s=43
2007-11-11 10:53:11 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
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2007-11-11 10:59:38 · update #1
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2007-11-11 10:55:47 · answer #1 · answered by dawn666annapolis 6 · 0⤊ 1⤋
7r-5s=1
5r+7s=43
Multiply 1st Eq by 7 and 2nd Eq by 5 getting:
49r -35s = 7
25r+35s = 215
Add the above two equations getting:
74r = 222
r = 3
so s = 4
2007-11-11 11:03:10 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
5r+7s=43.
7r-5s=1
Add both equations.
12r+2s=44.
Divide each side of the second equation by 2.
6r+s=22.
5r+7s=43
6r+s=22, Multiply the second equation by 7.
42r+7s=154.
Subtact the first equation and the third equation.
-37r=-111.
Divide each side by -37.
r=3.
You can find that s=4 afterwards.
2007-11-11 11:02:00 · answer #3 · answered by someone1254 2 · 0⤊ 0⤋
7r-5s=1......(1)
5r+7s=43......(2)
7*(1) + 5*(2): 74r = 222
r = 3
s = 4
2007-11-11 10:57:11 · answer #4 · answered by sahsjing 7 · 0⤊ 0⤋
R= 3
S=4
2007-11-11 10:57:20 · answer #5 · answered by My love is on your side ♥ 3 · 0⤊ 0⤋
r= 3
s=4
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2007-11-11 10:56:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋