Trig problem?

Question

Can someone help solve this trig equation?

10sin^2x - 7sinx - 6 = 0

Answer 1

factorize this like any other quad eq

(5sinx - 6)(2sinx + 1) = 0
sinx = 6/5 or sinx = -1/2

x = arcsin (-1/2)

Answer 2

10sin^2x - 7sinx - 6 = 0
(2 sin x + 1)(5 sin x - 6) = 0
2 sin x + 1 = 0 . . . . . . the other root is not valid
sin x = - 1/2
x = -30° = 330° . . . . . . x = 180 + 30 = 210°