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At a certain temperature K = 1.10×103 for the reaction:

Fe3+(aq) + SCN-(aq)= FeSCN2+(aq)

1.90×10-1 mol of Fe(NO3)3 is added to 1.27 L of 1.57×10-2 M KSCN.

Neglecting any volume change and assuming that all species remain in solution--:

Calculate the equilibrium concentration of Fe3+ (in mol/L).



Calculate the equilibrium concentration of SCN- (in mol/L).


Calculate the equilibrium concentration of FeSCN2+ (in mol/L).

2007-11-11 09:42:17 · 2 answers · asked by vik s 1 in Science & Mathematics Chemistry

2 answers

Please specify whether "FeSCN2+" in:
Fe3+(aq) + SCN-(aq)= FeSCN2+(aq)
is actually Fe(SCN)2(+) or FeSCN(2+)

2007-11-13 15:25:59 · answer #1 · answered by Hahaha 7 · 0 0

26.B,by means of fact it may merely be desperate by way of employing experiments 27.A , by means of fact the degree of the entire fee regulation won't exchange 28. C , by means of fact it makes the reaction swifter to overcome the activation capability

2016-12-16 05:33:24 · answer #2 · answered by ? 4 · 0 0

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