Please show your method!
2007-11-11 06:43:21 · 9 answers · asked by Millie E 1 in Science & Mathematics ➔ Mathematics
5² = 25
2007-11-11 07:03:03 · answer #1 · answered by Como 7 · 2⤊ 1⤋
Square the 125 and then find the cube root or better still, find the cube root of 125 which is 5 and then square it to give 25
Alternatively multiply the logarithm of 125 by 2/3 which is 2.09691*2/3 = 1.39794. The anti-log is 25. This is probably the best method especially when the cube root of the number is not straight forward.
2007-11-11 15:00:51 · answer #2 · answered by Anonymous · 0⤊ 1⤋
cube root of 125 = 5 then ^2 =25
2007-11-12 01:58:13 · answer #3 · answered by stuartelliott797 2 · 0⤊ 1⤋
you need to find the number root of the denominator which in your case is 3. so you find the cubed root of 125, which is 5. then do 5 to the power of the numeratorwhich in your case is 2. so you square it to give you 25. so your final answer is 25.
This method works for any fracional powers...
2007-11-11 15:49:24 · answer #4 · answered by Anonymous · 0⤊ 1⤋
125^(2/3)
=cubed root of (125^2)
=(cubed root of(125))^2
=5^2
=25
2007-11-11 14:52:56 · answer #5 · answered by Anonymous · 0⤊ 1⤋
125^(2/3)
= 5³^2/3
the cube and the denominator can cut it off, so
= 5²
= 25
*wink*
2007-11-12 05:29:39 · answer #6 · answered by m!l@ 2 · 0⤊ 1⤋
125^(2/3) = cubert(125^2)= 24
the denominator becomes the root factor in a fractional indice
2007-11-12 12:27:29 · answer #7 · answered by bendy_jo_jo 2 · 0⤊ 2⤋
125 = 5*5*5
so (125)[^1/3] = 5.
Now square that to get the answer.
2007-11-11 14:49:12 · answer #8 · answered by anthony@three-rs.com 3 · 0⤊ 1⤋
25
To see this, first factor 125 to get 5^3.
So you have
(5^3)^(2/3) =
5^(3*(2/3)) =
5^2 =
25
2007-11-11 14:47:25 · answer #9 · answered by Phineas Bogg 6 · 1⤊ 1⤋