How do i make x the subject of the equation?

Question

6 = (2x/x-1) + P/2????

Answer 1

12(x - 1) = 4x + P(x - 1)
12x - 12 = (4 + P)x - P
(8 - P)x = 12 - P
x = (12 - P) / (8 - P)

Answer 2

The first step is to get x off the bottom of the first fraction so we multiply each term by (x-1) to get:

6(x+1) = 2x + (x+1)P/2

but now we have x in a different fraction, so we multiply each term by 2 to get it out of this new one:

12(x+1) = 4x + (x+1)P

Now we need to multiply out the brackets:

12x + 12 = 4x + Px + P

Then gather all the x's to one side, all the terms without x to the other:

12x - 4x - Px = P - 12

Now we can take out x as a common factor on the right hand side:

x(12-4-P) = P-12

Then divide by (12-4-P) to leave x on it's own:

x= (P-12)/(12-4-P)

We can simplify the bottom of the fraction slightly:

x= (P-12)/(8-P)

Answer 3

6- P/2=2x/(x-1)

(6- P/2)(x-1)=2x
find x use distributive property

Answer 4

i hav no idea mate, havn't done that for ages, i end up with x= 7/p let me know wat' s the correct answer