Physics question help on kinetic energy, inelastic collisions?

Question

Here is the question:
Two balls of mud collide head-on in a perfectly inelastic collision. Their respective masses are m1=0.5kh and m2=0.25kg. m1 ismoving left to right before the collision with a speed of 4m/s and m2 is moving from right to left before the collision with a aspeed pf 3m/s. (a) Find the speed of the composite ball after the collsion (b) How much kinetic energy is lost during the collision?

Answer 1

Use conservation of momentum to figure out the final speed.
Find the momentum for each ball of mud before they collide. The sum of these will equal the momentum after colliding. Keep in mind that momentum is a vector. You can't just add their magnitudes. Make an equation equating the final and initial momentum. The only unknown in this equation will be velocity. So you can find the velocity. From this it is an easy matter to figure out the initial and final kinetic energies.

Answer 2

This undertaking is very complicated me besides.what's the question? i ought to have the capacity to easily right wager that the question is: at what techniques-set is the rope linked to the sector. is this the question? if so, answer as follows: with the aid of fact the sector strikes at a soft speed, the consequent or information superhighway rigidity is 0. subsequently the appliedpersistent in a horizontal course have have been given to be equivalent to the frictionpersistent: utilized rigidity horizontal course = 25N 25N is the horizontal element of a 43N rigidity at an attitude ? with the floor. clean up for ?. Cos ? = 25/40 3 cos ? = 0.5814 ? = fifty 4.40 5° above the horizontal The rope develop into at an techniques-set of fifty 4.40 5° above the horizontal